are we considering a real life scenario (have to account for air resistance and potentially wind) or theoretical?If I launch a projectile from ground level at a 20-degree angle how high will it be off of the ground when it crosses a line on the ground 10 feet away?
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140mphBtw, this might help:
https://ophysics.com/k8.html
Seems initial velocity is necessary to calculate it appropriately.
I went to an angle calculator and couldn't figure it out. Not that one, but another one. Speed shouldn't really be necessary, I mean, it's a triangle. Just trying to figure out how long the sides are. If one angle is 20, the other two are going to be 80, right? And one side is 10ft.
Actually, no, the angles of the triangle would be 20, 90, and 70.
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I think treating it like a triangle takes too many other factors out of the equation (velocity, gravity, etc) for you to obtain a correct answer
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Found a triangle calculator. 3.6ft.
Side a = 3.6397
Side b = 10.64178
Side c = 10
Thanks for making me answer my own stupid question.
Side a = 3.6397
Side b = 10.64178
Side c = 10
Thanks for making me answer my own stupid question.
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speed matters. something shot at 1 mph won’t make it 10 feet without hitting the ground
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140 mphI think treating it like a triangle takes too many other factors out of the equation (velocity, gravity, etc) for you to obtain a correct answer
The projectile is a 1.62 ounce sphere with a 1.68 inch diameter, spinning ~2200 rpm.
997' above sea level
80 degrees Fahrenheit ambient
Go for it.
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140 MPHspeed matters. something shot at 1 mph won’t make it 10 feet without hitting the ground
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are you looking for an exact number or estimate? if exact, you're still missing too much info and a CFD analysis would most likely be necessary
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Just an estimate. No way under real-world conditions do I continually launch the sphere at a consistent angle anyway.
I'm happy with my 3.6ft. If you guys want to keep working on it for some reason go ahead.
I'm happy with my 3.6ft. If you guys want to keep working on it for some reason go ahead.
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Yeah... I'm more on the practical side of this one. Go hit your golf ball at something that will leave a mark if you want a super realistic answer. If not, your triangle method is easy enough.
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speed matters dodint
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I think his example would be using a straight line thoughYeah... I'm more on the practical side of this one. Go hit your golf ball at something that will leave a mark if you want a super realistic answer. If not, your triangle method is easy enough.
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Golf ball flight is 250 yards. You're quibbling about the first 3 yards of flight.
The question on my mind is should I get a 10ft high net or a 15ft high net if I want to stand x feet from the net so a launch monitor can collect enough data to return meaningful numbers. If the Triangle calculator says 3.6ft and that's consistent with practical observation (as you said) in the simulator I visit a few times a week then that's good enough. The Triangle calculator would have to be off by a factor of about 2.5 for it to hurt me.
I reckon the simulator screen is 10ft high and I rarely miss it (shank/hosel). My runout area behind the net would be about 60 yards, and beyond that is woods. So even if a ball evades the net and gets around it's probably not making it to the woods.
The longer the ball can actually fly the more accurate the launch monitor numbers are so I have to see what distance makes the most sense. I'm trying to decide between making a 15ft net and frame, or buying an off-the-shelf 10ft solution.
The question on my mind is should I get a 10ft high net or a 15ft high net if I want to stand x feet from the net so a launch monitor can collect enough data to return meaningful numbers. If the Triangle calculator says 3.6ft and that's consistent with practical observation (as you said) in the simulator I visit a few times a week then that's good enough. The Triangle calculator would have to be off by a factor of about 2.5 for it to hurt me.
I reckon the simulator screen is 10ft high and I rarely miss it (shank/hosel). My runout area behind the net would be about 60 yards, and beyond that is woods. So even if a ball evades the net and gets around it's probably not making it to the woods.
The longer the ball can actually fly the more accurate the launch monitor numbers are so I have to see what distance makes the most sense. I'm trying to decide between making a 15ft net and frame, or buying an off-the-shelf 10ft solution.
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just wait until you hit underneath one, it skies and you hit whatever is behind the net
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Again... African or European?
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The 60 yards of open field or the woods?
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MIMH is joking but even at 25 degrees instead of 20 degrees you're looking at 4.6 ft vs. 3.6 ft
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Right. But there comes a point where missing the net just means a ballooned shot that doesn't leave the yard. There is nothing back there to hit, it's wooded. The net really just aids in the retention and retrieval of golf balls. If I hated the environment I'd just buy those big buckets of used range balls and fill the woods with them.
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Ok, my turn...ping pong ball, size 6 woman, three memory foam pillows...
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Ok, my turn...ping pong ball, size 6 woman, three memory foam pillows...
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How does the pop-up mechanism in my toaster work? You push down and it holds until the toast is done and then it pops up.
I ask because mine works intermittently and I have to jiggle it sometimes to get it to hold. But I can't picture how it even works to figure out why it only works some of the time.
I ask because mine works intermittently and I have to jiggle it sometimes to get it to hold. But I can't picture how it even works to figure out why it only works some of the time.
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I'd imagine there is a solenoid that holds it back until some kind of internal timer controlled via the settings knob tells it to release.
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I thought the mechanism was mechanical. The answer that is simply electronically controlled displeases me.
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Dang, I was close.
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